# Find vector equation and parametric equations for line

Since the line is perpendicular to the plane, the normal vector $\langle 1,3,1\rangle$ for the plane is parallel to the line, so the line has vector equation \$\langle x,y,z \rangle=\langle 1,0,6\rangle

## The vector and parametric equations of a line segment

The vector equation of a line is given by: where v is the direction vector, and is a point of the line. So, for this case, the line pass for the point (0, 11, −8): With the direction, the

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## Find a vector equation and parametric equations for the line.

⎧ ⎨⎩x = 2t y = 14 − 3t z = − 10 +9t Explanation: The usual parametric representation is written as p = p0 + t→ v. Here we have p = {x,y,z} p0 = { −1,6,3} t ∈ R → v = {2, −3,9} So, given p1 = {0,14, −10} the parallel line is

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## 10) and parallel to the line:x = -1+2t, y = 6-3t, z = 3+9t?

line!The relationship between the vector and parametric equations of a line segment. Sometimes we need to find the equation of a line segment when we only have the endpoints of the line segment. The vector equation of the line

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## Equations of Lines

Find a vector equation and parametric equations for the line. (Use the parameter t.) The line through the point (1, 0, 9) and perpendicular to the plane x + 2y + z = 7 r(t) = (x(t), y(t), z(t)) =

## Find a vector equation and parametric equations for the line

Calculus questions and answers. Find a vector equation and parametric equations for the line through the point 𝑷𝟎 (𝟔, −𝟓, 𝟐) and parallel to the vector . (b) : Find an equation of the plane

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## Solved Find a vector equation and parametric

Find a vector equation and parametric equations for the line. (Use the parameter t.) the line through the point (8,0,-3) and parallel to the line x = 4 – 47, y=-1 + 30, z = 6+ 7+ r (t) = (te). (e)

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