The vector equation of a line is given by: where v is the direction vector, and is a point of the line. So, for this case, the line pass for the point (0, 11, −8): With the direction, the
⎧ ⎨⎩x = 2t y = 14 − 3t z = − 10 +9t Explanation: The usual parametric representation is written as p = p0 + t→ v. Here we have p = {x,y,z} p0 = { −1,6,3} t ∈ R → v = {2, −3,9} So, given p1 = {0,14, −10} the parallel line is
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line!The relationship between the vector and parametric equations of a line segment. Sometimes we need to find the equation of a line segment when we only have the endpoints of the line segment. The vector equation of the line
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Calculus questions and answers. Find a vector equation and parametric equations for the line through the point 𝑷𝟎 (𝟔, −𝟓, 𝟐) and parallel to the vector . (b) : Find an equation of the plane
Find a vector equation and parametric equations for the line. (Use the parameter t.) the line through the point (8,0,-3) and parallel to the line x = 4 – 47, y=-1 + 30, z = 6+ 7+ r (t) = (te). (e)
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