We are given the coordinates of a point, so: {eq}x_1 = 2 \\ y_1 = 1 {/eq} Now, substitute all the values into the point-slope formula: {eq}y - 1 =3(x - 2) {/eq} Simplify and solve for y:

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The equation of a circle is x2 + y2 = r2. Based on this equation and the coordinates of the point, ( x, y ), where the terminal side of the angle intersects the circle, the six trig

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Let the required point on the curve be ( k, k 2 − 3). Then the slope of the tangent at that point equals 2 k. Further we know it passes through two points ( − 2, 0) and ( k, k 2 − 3). So, lets

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