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Calculate a formula for the general term based on the terms of an arithmetic sequence: a1=6anda7=42; A1=12anda12=6; A1=19anda26=56; A1=9anda31=141;
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Find a1 of arithmetic sequence from given information. a7 = -45 a15 = -77. Use the formula: an = a1 + (n-1)d. a7 = a1 + (7-1)d. -45 = a1 + 6d. a15 = a1 + (15-1)d. -77 = a1 + 14d. So you have this
If a1 is the first term of an arithmetic sequence and d is the common difference, then the formula for finding the nth term of the sequence is an = a1 + (n – 1)d. We have been
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- the mean value of arithmetic series is x̅; - standard deviation of any arithmetic progression is σ. Then: a n = a 1 + d(n - 1) S = [n(a 1 +a n)]/2. x̅ = (a 1 +a n) /2. σ = |d|*√((n-1)*(n+1)/12) Example
The answer to this math question is 42.
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