I took derivative of the quadratic and got V=24t-6t^2 and set it =0, then i solve for t and substituted in x=12t^2-2t^3 to get the max. positive coordinate. But I don't know what to

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If we want to find the maximum velocity, we take the derivative of velocity (which is acceleration) and find where the derivative is zero. v ′ ( t) = 12 t − 24 Next, we set the derivative equal to zero

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