Solve for t three(t plus five) equals six minus two(t minus four)

$3 (t + 5) = 6 - 2 (t - 4)$

Clarify $3 (t + 5)$ .

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Use the distributive law.

$3 t + 3 \cdot 5 = 6 - 2 (t - 4)$

First, multiply $3$ by $5$ .

$3 t + 15 = 6 - 2 (t - 4)$

Simplify $6 - 2 (t - 4)$ .

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Clarify each term.

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Apply the distributive property.

$3 t + 15 = 6 - 2 t - 2 \cdot - 4$

Multiply $- 2$ by $- 4$ .

$3 t + 15 = 6 - 2 t + 8$

Add $6$ and $8$ .

$3 t + 15 = - 2 t + 14$

Move all terms containing $t$ to the left side of the equation.

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Add $2 t$ to both sides of the equation.

$3 t + 15 + 2 t = 14$

Add $3 t$ and $2 t$ .

$5 t + 15 = 14$

Move all terms not containing $t$ to the right side of the equation.

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Subtract $15$ from both sides of the equation.

$5 t = 14 - 15$

Subtract $15$ from $14$ .

$5 t = - 1$

First, divide each term by $5$ and simplify.

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Divide each term in $5 t = - 1$ by $5$ .

$\frac{5 t}{5} = \frac{- 1}{5}$

The common factor should be canceled of $5$ .

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Cancel the common factor.

$\frac{5 t}{5} = \frac{- 1}{5}$

Divide $t$ by $1$ .

$t = \frac{- 1}{5}$

Put the negative in front of the fraction.

$t = - \frac{1}{5}$

The result can be displayed in a variety of ways.

Exact Form:

$t = - \frac{1}{5}$

Decimal Form:

$t = - 0.2$

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