Find the Derivative minus d First, divide dx cos(two x)

$\cos (2 x)$

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = \cos (x)$ and $g (x) = 2 x$ .

Tap for more steps...

To apply the Chain Rule, set $u$ as $2 x$ .

$\frac{d}{d u} [\cos (u)] \frac{d}{d x} [2 x]$

The derivative of $\cos (u)$ with respect to $u$ is $- \sin (u)$ .

$- \sin (u) \frac{d}{d x} [2 x]$

Replace all occurrences of $u$ with $2 x$ .

$- \sin (2 x) \frac{d}{d x} [2 x]$

Differentiate.

Tap for more steps...

Since $2$ is constant with respect to $x$ , the derivative of $2 x$ with respect to $x$ is $2 \frac{d}{d x} [x]$ .

$- \sin (2 x) (2 \frac{d}{d x} [x])$

First, First, multiply $2$ by $- 1$ .

$- 2 \sin (2 x) \frac{d}{d x} [x]$

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$- 2 \sin (2 x) \cdot 1$

Multiply $- 2$ by $1$ .

$- 2 \sin (2 x)$

Do you need help with solving Find the Derivative - d/dx cos(2x)? We can help you. You can write to our math experts in our application. The best solution for you is above on this page.

Find the Derivative minus d First, divide dx f(x) equals e to the power of x

Evaluate integral of natural log of x with respect to x

Find the Derivative minus d First, divide dt cos((pit) divide four)

Find the Derivative minus d First, divide dx y equals minus(x to the power of two) divide sixteen plus two divide x minus x to the power of(three divide two) plus one divide(three x to the power of two) plus x divide three

Find dy First, divide dx square root of xy equals four plus x to the power of two y