Find the Derivative minus d First, divide dx xe to the power of x

$x e^{x}$

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = x$ and $g (x) = e^{x}$ .

$x \frac{d}{d x} [e^{x}] + e^{x} \frac{d}{d x} [x]$

Differentiate using the Exponential Rule which states that $\frac{d}{d x} [a^{x}]$ is $a^{x} \ln (a)$ where $a$ = $e$ .

$x e^{x} + e^{x} \frac{d}{d x} [x]$

Differentiate using the Power Rule.

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Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$x e^{x} + e^{x} \cdot 1$

Clarify the expression.

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First, multiply $e^{x}$ by $1$ .

$x e^{x} + e^{x}$

Shift terms.

$e^{x} x + e^{x}$

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