Find the Derivative minus d First, divide dx ( natural log of x) to the power of two

$\ln^{2} (x)$

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{2}$ and $g (x) = \ln (x)$ .

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To apply the Chain Rule, set $u$ as $\ln (x)$ .

$\frac{d}{d u} [u^{2}] \frac{d}{d x} [\ln (x)]$

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = 2$ .

$2 u \frac{d}{d x} [\ln (x)]$

Replace all occurrences of $u$ with $\ln (x)$ .

$2 \ln (x) \frac{d}{d x} [\ln (x)]$

The derivative of $\ln (x)$ with respect to $x$ is $\frac{1}{x}$ .

$2 \ln (x) \frac{1}{x}$

Add fractions.

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Add $\frac{1}{x}$ and $2$ .

$\frac{2}{x} \ln (x)$

Combine $\frac{2}{x}$ and $\ln (x)$ .

$\frac{2 \ln (x)}{x}$

Clarify $2 \ln (x)$ by moving $2$ inside the logarithm.

$\frac{\ln (x^{2})}{x}$

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