Find the Derivative minus d First, divide dx y equals sixteen fourth root of four x to the power of four plus four

$y = 16 \sqrt[4]{4 x^{4} + 4}$

Differentiate using the Constant Multiple Rule.

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Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to Should be rewritten $\sqrt[4]{4 x^{4} + 4}$ as ${(4 x^{4} + 4)}^{\frac{1}{4}}$ .

$\frac{d}{d x} [16 {(4 x^{4} + 4)}^{\frac{1}{4}}]$

Since $16$ is constant with respect to $x$ , the derivative of $16 {(4 x^{4} + 4)}^{\frac{1}{4}}$ with respect to $x$ is $16 \frac{d}{d x} [{(4 x^{4} + 4)}^{\frac{1}{4}}]$ .

$16 \frac{d}{d x} [{(4 x^{4} + 4)}^{\frac{1}{4}}]$

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{\frac{1}{4}}$ and $g (x) = 4 x^{4} + 4$ .

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To apply the Chain Rule, set $u$ as $4 x^{4} + 4$ .

$16 (\frac{d}{d u} [u^{\frac{1}{4}}] \frac{d}{d x} [4 x^{4} + 4])$

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = \frac{1}{4}$ .

$16 (\frac{1}{4} u^{\frac{1}{4} - 1} \frac{d}{d x} [4 x^{4} + 4])$

Replace all occurrences of $u$ with $4 x^{4} + 4$ .

$16 (\frac{1}{4} {(4 x^{4} + 4)}^{\frac{1}{4} - 1} \frac{d}{d x} [4 x^{4} + 4])$

To write $- 1$ as a fraction with a common denominator, First, multiply by $\frac{4}{4}$ .

$16 (\frac{1}{4} {(4 x^{4} + 4)}^{\frac{1}{4} - 1 \cdot \frac{4}{4}} \frac{d}{d x} [4 x^{4} + 4])$

Add $- 1$ and $\frac{4}{4}$ .

$16 (\frac{1}{4} {(4 x^{4} + 4)}^{\frac{1}{4} + \frac{- 1 \cdot 4}{4}} \frac{d}{d x} [4 x^{4} + 4])$

Add numerators over the common denominator.

$16 (\frac{1}{4} {(4 x^{4} + 4)}^{\frac{1 - 1 \cdot 4}{4}} \frac{d}{d x} [4 x^{4} + 4])$

Clarify the numerator.

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Multiply $- 1$ by $4$ .

$16 (\frac{1}{4} {(4 x^{4} + 4)}^{\frac{1 - 4}{4}} \frac{d}{d x} [4 x^{4} + 4])$

Subtract $4$ from $1$ .

$16 (\frac{1}{4} {(4 x^{4} + 4)}^{\frac{- 3}{4}} \frac{d}{d x} [4 x^{4} + 4])$

Put the negative in front of the fraction.

$16 (\frac{1}{4} {(4 x^{4} + 4)}^{- \frac{3}{4}} \frac{d}{d x} [4 x^{4} + 4])$

Combine $\frac{1}{4}$ and ${(4 x^{4} + 4)}^{- \frac{3}{4}}$ .

$16 (\frac{{(4 x^{4} + 4)}^{- \frac{3}{4}}}{4} \frac{d}{d x} [4 x^{4} + 4])$

Move ${(4 x^{4} + 4)}^{- \frac{3}{4}}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$16 (\frac{1}{4 {(4 x^{4} + 4)}^{\frac{3}{4}}} \frac{d}{d x} [4 x^{4} + 4])$

Combine $\frac{1}{4 {(4 x^{4} + 4)}^{\frac{3}{4}}}$ and $16$ .

$\frac{16}{4 {(4 x^{4} + 4)}^{\frac{3}{4}}} \frac{d}{d x} [4 x^{4} + 4]$

Factor $4$ out of $16$ .

$\frac{4 \cdot 4}{4 {(4 x^{4} + 4)}^{\frac{3}{4}}} \frac{d}{d x} [4 x^{4} + 4]$

The common factor should be canceleds.

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Factor $4$ out of $4 {(4 x^{4} + 4)}^{\frac{3}{4}}$ .

$\frac{4 \cdot 4}{4 ({(4 x^{4} + 4)}^{\frac{3}{4}})} \frac{d}{d x} [4 x^{4} + 4]$

Cancel the common factor.

$\frac{4 \cdot 4}{4 {(4 x^{4} + 4)}^{\frac{3}{4}}} \frac{d}{d x} [4 x^{4} + 4]$

Reformulate the expression.

$\frac{4}{{(4 x^{4} + 4)}^{\frac{3}{4}}} \frac{d}{d x} [4 x^{4} + 4]$

By the Sum Rule, the derivative of $4 x^{4} + 4$ with respect to $x$ is $\frac{d}{d x} [4 x^{4}] + \frac{d}{d x} [4]$ .

$\frac{4}{{(4 x^{4} + 4)}^{\frac{3}{4}}} (\frac{d}{d x} [4 x^{4}] + \frac{d}{d x} [4])$

Since $4$ is constant with respect to $x$ , the derivative of $4 x^{4}$ with respect to $x$ is $4 \frac{d}{d x} [x^{4}]$ .

$\frac{4}{{(4 x^{4} + 4)}^{\frac{3}{4}}} (4 \frac{d}{d x} [x^{4}] + \frac{d}{d x} [4])$

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 4$ .

$\frac{4}{{(4 x^{4} + 4)}^{\frac{3}{4}}} (4 (4 x^{3}) + \frac{d}{d x} [4])$

Multiply $4$ by $4$ .

$\frac{4}{{(4 x^{4} + 4)}^{\frac{3}{4}}} (16 x^{3} + \frac{d}{d x} [4])$

Since $4$ is constant with respect to $x$ , the derivative of $4$ with respect to $x$ is $0$ .

$\frac{4}{{(4 x^{4} + 4)}^{\frac{3}{4}}} (16 x^{3} + 0)$

Add fractions.

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Add $16 x^{3}$ and $0$ .

$\frac{4}{{(4 x^{4} + 4)}^{\frac{3}{4}}} (16 x^{3})$

Combine $16$ and $\frac{4}{{(4 x^{4} + 4)}^{\frac{3}{4}}}$ .

$\frac{16 \cdot 4}{{(4 x^{4} + 4)}^{\frac{3}{4}}} x^{3}$

First, multiply $16$ by $4$ .

$\frac{64}{{(4 x^{4} + 4)}^{\frac{3}{4}}} x^{3}$

Combine $\frac{64}{{(4 x^{4} + 4)}^{\frac{3}{4}}}$ and $x^{3}$ .

$\frac{64 x^{3}}{{(4 x^{4} + 4)}^{\frac{3}{4}}}$

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