# Find the Oxidation Numbers C_ six H_ twelve O_ six

Since is in column of the periodic table, it will share electrons and use an oxidation state of .

Since is in column of the periodic table, it will share electrons and use an oxidation state of .

To find the oxidation state of , set up an equation of each oxidation state found earlier and set it equal to .

Clarify .

Add and .

Sum and .

First, divide each term by and simplify.

Divide each term in by .

The common factor should be canceled of .

Cancel the common factor.

Divide by .

Initially, divide by .

is using an oxidation state of .

This is the full list of oxidation states for this molecule.

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