Graph y equals four x plus two

$y = 4 x + 2$

Use the slope-intercept form to find the slope and y-intercept.

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The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = 4$

$b = 2$

The value of $m$ is the gradient of the line, and the y-intercept is the value of $b$ .

Slope: $4$

y-intercept: $2$

Slope: $4$

y-intercept: $2$

Any line can be graphed using two points. Select two $x$ values, and plug them into the equation to find the corresponding $y$ values.

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Choose $0$ to substitute in for $x$ to find the ordered pair.

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Replace the variable $x$ with $0$ in the expression.

$f (0) = 4 (0) + 2$

Clarify the result.

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Initially, First, multiply $4$ by $0$ .

$f (0) = 0 + 2$

Sum $0$ and $2$ .

$f (0) = 2$

The result is $2$ .

$2$

The $y$ value at $x = 0$ is $2$ .

$y = 2$

Choose $1$ to substitute in for $x$ to find the ordered pair.

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Replace the variable $x$ with $1$ in the expression.

$f (1) = 4 (1) + 2$

Clarify the result.

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Multiply $4$ by $1$ .

$f (1) = 4 + 2$

Add $4$ and $2$ .

$f (1) = 6$

The result is $6$ .

$6$

The $y$ value at $x = 1$ is $6$ .

$y = 6$

Create a table of the $x$ and $y$ values.

$\begin{array}{c} x & y \\ 0 & 2 \\ 1 & 6 \end{array}$

Plot the line with the slope and the y-intercept, or the points.

Slope: $4$

y-intercept: $2$

$\begin{array}{c} x & y \\ 0 & 2 \\ 1 & 6 \end{array}$

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