Graph x minus y equals five

$x - y = 5$

Calculate $y$ .

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Subtract $x$ from both sides of the equation.

$- y = 5 - x$

First, multiply each term in $- y = 5 - x$ by $- 1$

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Multiply each term in $- y = 5 - x$ by $- 1$ .

$(- y) \cdot - 1 = 5 \cdot - 1 + (- x) \cdot - 1$

Multiply $(- y) \cdot - 1$ .

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Multiply $- 1$ by $- 1$ .

$1 y = 5 \cdot - 1 + (- x) \cdot - 1$

Multiply $y$ by $1$ .

$y = 5 \cdot - 1 + (- x) \cdot - 1$

Clarify each term.

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Multiply $5$ by $- 1$ .

$y = - 5 + (- x) \cdot - 1$

Multiply $(- x) \cdot - 1$ .

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Multiply $- 1$ by $- 1$ .

$y = - 5 + 1 x$

Multiply $x$ by $1$ .

$y = - 5 + x$

Should be rewritten in slope-intercept form.

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The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Shift $- 5$ and $x$ .

$y = x - 5$

Use the slope-intercept form to find the slope and y-intercept.

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Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = 1$

$b = - 5$

The value of $m$ is the gradient of the line, and the y-intercept is the value of $b$ .

Slope: $1$

y-intercept: $- 5$

Slope: $1$

y-intercept: $- 5$

Any line can be graphed using two points. Select two $x$ values, and plug them into the equation to find the corresponding $y$ values.

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Choose $2$ to substitute in for $x$ to find the ordered pair.

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Replace the variable $x$ with $2$ in the expression.

$f (2) = (2) - 5$

Clarify the result.

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Subtract $5$ from $2$ .

$f (2) = - 3$

The result is $- 3$ .

$- 3$

The $y$ value at $x = 2$ is $- 3$ .

$y = - 3$

Choose $3$ to substitute in for $x$ to find the ordered pair.

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Replace the variable $x$ with $3$ in the expression.

$f (3) = (3) - 5$

Clarify the result.

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Subtract $5$ from $3$ .

$f (3) = - 2$

The result is $- 2$ .

$- 2$

The $y$ value at $x = 3$ is $- 2$ .

$y = - 2$

Create a table of the $x$ and $y$ values.

$\begin{array}{c} x & y \\ 2 & - 3 \\ 3 & - 2 \end{array}$

Plot the line with the slope and the y-intercept, or the points.

Slope: $1$

y-intercept: $- 5$

$\begin{array}{c} x & y \\ 2 & - 3 \\ 3 & - 2 \end{array}$

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