Solve for x (two x minus one) divide(x plus two) equals four First, divide five

$\frac{2 x - 1}{x + 2} = \frac{4}{5}$

First, multiply the Initially fraction's numerator by the second fraction's denominator. Make this equal to the product of the second fraction's numerator and first fraction's denominator.

$(2 x - 1) \cdot 5 = (x + 2) \cdot 4$

Calculate $x$ in the equation.

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Clarify $(2 x - 1) \cdot 5$ .

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Use the distributive law.

$2 x \cdot 5 - 1 \cdot 5 = (x + 2) \cdot 4$

Multiply.

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Multiply $5$ by $2$ .

$10 x - 1 \cdot 5 = (x + 2) \cdot 4$

Multiply $- 1$ by $5$ .

$10 x - 5 = (x + 2) \cdot 4$

Simplify $(x + 2) \cdot 4$ .

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Apply the distributive property.

$10 x - 5 = x \cdot 4 + 2 \cdot 4$

Clarify the expression.

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Move $4$ to the left of $x$ .

$10 x - 5 = 4 \cdot x + 2 \cdot 4$

First, multiply $2$ by $4$ .

$10 x - 5 = 4 x + 8$

Move all terms containing $x$ to the left side of the equation.

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Subtract $4 x$ from both sides of the equation.

$10 x - 5 - 4 x = 8$

Subtract $4 x$ from $10 x$ .

$6 x - 5 = 8$

Move all terms not containing $x$ to the right side of the equation.

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Add $5$ to both sides of the equation.

$6 x = 8 + 5$

Add $8$ and $5$ .

$6 x = 13$

Divide each term by $6$ and simplify.

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Divide each term in $6 x = 13$ by $6$ .

$\frac{6 x}{6} = \frac{13}{6}$

The common factor should be canceled of $6$ .

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Cancel the common factor.

$\frac{6 x}{6} = \frac{13}{6}$

Divide $x$ by $1$ .

$x = \frac{13}{6}$

The result can be displayed in a variety of ways.

Exact Form:

$x = \frac{13}{6}$

Decimal Form:

$x = 2.1\overline{6}$

Mixed Number Form:

$x = 2 \frac{1}{6}$

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