Evaluate sum from i equals one to four of four n plus one

$\sum_{i = 1}^{4} 4 n + 1$

Expand the series for each value of $i$ .

$4 n + 1 + 4 n + 1 + 4 n + 1 + 4 n + 1$

Simplify.

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Add $4 n$ and $4 n$ .

$8 n + 1 + 1 + 4 n + 1 + 4 n + 1$

Add $8 n$ and $4 n$ .

$12 n + 1 + 1 + 1 + 4 n + 1$

Add $12 n$ and $4 n$ .

$16 n + 1 + 1 + 1 + 1$

Clarify by adding numbers.

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Add $1$ and $1$ .

$16 n + 2 + 1 + 1$

Add $2$ and $1$ .

$16 n + 3 + 1$

Add $3$ and $1$ .

$16 n + 4$

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