Simplify (x to the power of two minus four) divide(two x minus four)

$\frac{x^{2} - 4}{2 x - 4}$

Clarify the numerator.

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Should be rewritten $4$ as $2^{2}$ .

$\frac{x^{2} - 2^{2}}{2 x - 4}$

As both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = x$ and $b = 2$ .

$\frac{(x + 2) (x - 2)}{2 x - 4}$

Clarify terms.

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Factor $2$ out of $2 x - 4$ .

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Factor $2$ out of $2 x$ .

$\frac{(x + 2) (x - 2)}{2 (x) - 4}$

Factor $2$ out of $- 4$ .

$\frac{(x + 2) (x - 2)}{2 x + 2 \cdot - 2}$

Factor $2$ out of $2 x + 2 \cdot - 2$ .

$\frac{(x + 2) (x - 2)}{2 (x - 2)}$

The common factor should be canceled of $x - 2$ .

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Cancel the common factor.

$\frac{(x + 2) (x - 2)}{2 (x - 2)}$

Reformulate the expression.

$\frac{x + 2}{2}$

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