Find the Foci ((y minus two) to the power of two) divide sixty minus four minus((x minus four) to the power of two) divide thirty minus six equals one

Find the Foci ((y-2)^2)/64-((x-4)^2)/36=1
Clarify each term in the equation in order to set the right side equal to . The right side of the equation must equal for an ellipse or hyperbola to have the standard form.
This is the form of a hyperbola. Use this form to figure out the values used to calculate the hyperbola's vertices and asymptotes.
Compare the values in this hyperbola to those of the initial form. The variable represents the x-offset from the origin, represents the y-offset from origin, .
Calculate , the distance from the center to a focus.
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Find the distance from the center to a focus of the hyperbola by using the following formula.
Replace the values of and in the formula.
Simplify.
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Raise to the power of .
Raise to the power of .
Add and .
Should be rewritten as .
Withdraw terms from under the radical, assuming positive real numbers.
Find the foci.
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The Initially focus of a hyperbola can be found by adding to .
Replace the known values of , , and into the formula and simplify.
The second focus of a hyperbola can be found by subtracting from .
Substitute the known values of , , and into the formula and simplify.
The foci of a hyperbola follow the form of . Hyperbolas have two foci.
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