linear\:2y'-y=4\sin(3t) linear\:ty'+2y=t^2-t+1; linear\:ty'+2y=t^2-t+1,\:y(1)=\frac{1}{2} linear\:\frac{dv}{dt}=10-2v; linear\:\frac{dx}{dt}=5x-3
Finally, you can use another formula to find the general solution of the first order linear differential equation y = 1/I (x) [Integral (I (x)Q (x)dx + C]. This video contains plenty of
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Step1: Definition of first order linear differential equation. Consider the differential equation where is a smooth function and 'a' is a constant. Then the general solution will be . Solve the
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